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Meesho Placement Papers 2026

3 min read
Company Placement Papers
Last Updated: 1 May 2026
Reviewed by PapersAdda Editorial

Last Updated: March 2026


Company Overview

Meesho is India's largest social commerce platform enabling small businesses and individuals to start online stores via social media. It's a unicorn startup backed by top investors.

Key Facts:

  • Founded: 2015
  • Employees: 2000+
  • India Offices: Bangalore (HQ)
  • Valuation: $5+ billion

Eligibility Criteria

CriteriaRequirement
DegreeB.Tech/B.E, M.Tech, MCA
BranchesCSE, IT
Academic Score70%+ throughout
BacklogsNo active backlogs

CTC & Compensation

RoleCTC (Fresher)
Software Engineer12-20 LPA
Product Engineer14-22 LPA
Data Scientist15-25 LPA

Exam Pattern

SectionQuestionsDuration
Aptitude1520 min
Technical MCQ1520 min
Coding375 min

Aptitude Questions

Q1

A can do work in 20 days, B in 30 days. Together? Answer: 12 days

Q2

Speed ratio 3:4, time for same distance? Answer: 4:3

Q3

Ages ratio 3:5, sum is 48. Find difference? Answer: 12 years

Q4

CP:SP = 4:5. Profit %? Answer: 25%

Q5

Area of circle increased by 44%. Radius increased by? Answer: 20%


Technical Questions

  1. Difference between SQL JOIN types?
  2. Explain microservices vs monolith?
  3. What is eventual consistency?
  4. Rate limiting strategies?
  5. Cache eviction policies?

Coding Questions (Python)

Q1: Group Anagrams

def group_anagrams(strs):
    from collections import defaultdict
    groups = defaultdict(list)
    for s in strs:
        key = ''.join(sorted(s))
        groups[key].append(s)
    return list(groups.values())

Q2: Valid Parentheses

def is_valid(s):
    stack = []
    mapping = {')': '(', '}': '{', ']': '['}
    for char in s:
        if char in mapping:
            top = stack.pop() if stack else '#'
            if mapping[char] != top:
                return False
        else:
            stack.append(char)
    return not stack

Q3: Longest Substring Without Repeating Characters

def length_of_longest(s):
    char_set = set()
    left = max_len = 0
    for right in range(len(s)):
        while s[right] in char_set:
            char_set.remove(s[left])
            left += 1
        char_set.add(s[right])
        max_len = max(max_len, right - left + 1)
    return max_len

Interview Tips

  1. E-commerce Knowledge: Understand social commerce model
  2. Startup Mindset: Show ownership and hustle
  3. System Design: Basics of scalable systems
  4. Data Structures: Strong DSA fundamentals
  5. Problem Solving: Creative solutions to problems

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FAQs

Q1: Is Meesho hiring freshers? Yes, campus + off-campus Q2: Tech stack? Go, Java, Python, React, AWS Q3: Interview focus? Coding + System Design + Culture fit


All the best for your Meesho placement!

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