Ericsson Placement Papers 2026
Last Updated: March 2026
Company Overview
Ericsson is a Swedish multinational networking and telecommunications company. It's a leader in 5G technology and network infrastructure.
Key Facts:
- Founded: 1876
- Employees: 100,000+ globally
- India Offices: Bangalore, Chennai, Gurgaon, Pune
- Focus: 5G, Cloud, Network Infrastructure
Eligibility Criteria
| Criteria | Requirement |
|---|---|
| Degree | B.Tech/B.E, M.Tech |
| Branches | CSE, IT, ECE, EEE, Telecom |
| Academic Score | 65%+ throughout |
| Backlogs | No active backlogs |
CTC & Compensation
| Role | CTC (Fresher) |
|---|---|
| Associate Engineer | 4.5-7 LPA |
| Software Engineer | 5-8 LPA |
Exam Pattern
| Section | Questions | Duration |
|---|---|---|
| Aptitude | 20 | 25 min |
| Technical | 25 | 30 min |
| Coding | 2 | 45 min |
Aptitude Questions
Q1
Train 180m crosses platform in 24 sec at 54 km/hr. Platform length? Answer: 180m
Q2
A and B age ratio 4:5. After 5 years 5:6. Sum of present ages? Answer: 45 years
Q3
Successive discounts 20% and 10%. Single equivalent? Answer: 28%
Q4
Area of circle becomes 4 times. Radius becomes? Answer: 2 times
Q5
Permutations of "ENGINEER"? Answer: 3360
Technical Questions
- 5G vs 4G architecture
- What is NFV?
- SDN concepts
- Network slicing
- Cloud-native applications
Coding Questions (Python)
Q1: Longest Common Subsequence
def lcs(text1, text2):
m, n = len(text1), len(text2)
dp = [[0] * (n + 1) for _ in range(m + 1)]
for i in range(1, m + 1):
for j in range(1, n + 1):
if text1[i-1] == text2[j-1]:
dp[i][j] = dp[i-1][j-1] + 1
else:
dp[i][j] = max(dp[i-1][j], dp[i][j-1])
return dp[m][n]
Q2: Topological Sort
def topological_sort(graph, n):
in_degree = [0] * n
for u in range(n):
for v in graph[u]:
in_degree[v] += 1
queue = [i for i in range(n) if in_degree[i] == 0]
result = []
while queue:
u = queue.pop(0)
result.append(u)
for v in graph[u]:
in_degree[v] -= 1
if in_degree[v] == 0:
queue.append(v)
return result if len(result) == n else []
Q3: Sliding Window Maximum
from collections import deque
def max_sliding_window(nums, k):
result = []
dq = deque()
for i, num in enumerate(nums):
while dq and nums[dq[-1]] < num:
dq.pop()
dq.append(i)
if dq[0] <= i - k:
dq.popleft()
if i >= k - 1:
result.append(nums[dq[0]])
return result
Interview Tips
- Telecom Knowledge: 4G, 5G basics
- Networking: Strong fundamentals
- Cloud Technologies: Docker, Kubernetes
- Global Mindset: Multinational culture
- Innovation Focus: Ericsson's R&D culture
FAQs
Q1: Does Ericsson hire freshers? Yes, through campus Q2: Bond period? 1 year typical Q3: Tech focus? 5G, Cloud, Automation
All the best for your Ericsson placement!
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