Infosys SP DSE Placement Papers 2026

Last Updated: March 2026

Infosys SP (Specialist Programmer) and DSE (Digital Specialist Engineer) are premium hiring tracks at Infosys, offering significantly higher packages than the standard role. These tracks are designed for candidates with exceptional technical and problem-solving abilities.

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Infosys SP & DSE Program Overview

Aspect	Infosys SP	Infosys DSE
Full Form	Specialist Programmer	Digital Specialist Engineer
Package	₹8-9 LPA	₹6-7 LPA
Role	Specialist Programmer	Digital Specialist Engineer
Work	High-end technical projects	Digital transformation projects
Eligibility	70%+ throughout	65%+ throughout

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Eligibility Criteria

Infosys SP

• Academic: Minimum 70% throughout (10th, 12th, Graduation)
• Degree: BE/B.Tech/ME/M.Tech (CS/IT/ECE/EEE preferred)
• Backlogs: No active backlogs
• Skills: Strong coding and problem-solving skills

Infosys DSE

• Academic: Minimum 65% throughout
• Degree: BE/B.Tech/ME/M.Tech/MCA/M.Sc
• Backlogs: No active backlogs
• Skills: Good technical knowledge and aptitude

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Exam Pattern Comparison

Section	Infosys SP	Infosys DSE
Aptitude Test	Yes (Advanced)	Yes (Standard)
Technical MCQs	Yes (Advanced)	Yes
Coding Round 1	2 Questions	2 Questions
Coding Round 2	2 Questions (Hard)	1-2 Questions
Technical Interview	Advanced	Moderate-Advanced
HR Interview	Yes	Yes

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15 Sample Questions with Solutions

Advanced Aptitude (Questions 1-4)

Q1. A train passes a platform in 30 seconds and a man standing on the platform in 15 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

• a) 200m
• b) 225m
• c) 250m
• d) 300m

Solution: Speed = 54 × (5/18) = 15 m/s. Train length = 15 × 15 = 225m. Platform + Train = 15 × 30 = 450m. Platform = 450 - 225 = 225m.

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Q2. In how many ways can the letters of the word 'LEADING' be arranged so that the vowels always come together?

• a) 480
• b) 720
• c) 5040
• d) 1440

Solution: Treat vowels EAI as one unit. We have LNDG + (EAI) = 5 units. Arrangements = 5! × 3! = 120 × 6 = 720.

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Q3. A and B invest in a business in the ratio 3:2. If 5% of the total profit goes to charity and A's share is ₹855, what is the total profit?

• a) ₹1400
• b) ₹1500
• c) ₹1600
• d) ₹1700

Solution: Let total profit = P. After charity: 0.95P. A's share = (3/5) × 0.95P = 855. So P = 855 × 5 / (3 × 0.95) = 1500.

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Q4. The compound interest on a sum for 2 years at 10% per annum is ₹840. What would be the simple interest for the same period?

• a) ₹700
• b) ₹750
• c) ₹800
• d) ₹850

Solution: CI = P[(1.1)² - 1] = 0.21P = 840, so P = 4000. SI = 4000 × 0.10 × 2 = 800.

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Logical Reasoning (Questions 5-7)

Q5. Statement: All engineers are intelligent. Some intelligent people are creative. Conclusions: I. All engineers are creative II. Some creative people are engineers

• a) Only I follows
• b) Only II follows
• c) Both follow
• d) Neither follows

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Q6. In a certain code, COMPUTER is written as RFUVQNPC. How is MEDICINE written in that code?

• a) EOJDJEFM
• b) EOJDEJFM
• c) MFEJDJOE
• d) MFEDJJOE

Explanation: Letters are reversed and each letter is shifted +1.

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Q7. Find the odd one out: 3, 9, 27, 81, 243, 728

• a) 9
• b) 27
• c) 243
• d) 728

Explanation: All are powers of 3 except 728 (3⁶ = 729, not 728).

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Technical MCQs (Questions 8-10)

Q8. What is the output of the following C code?

int x = 10;
printf("%d %d %d", x, ++x, x++);

• a) 10 11 11
• b) 11 11 10
• c) 12 12 10
• d) Compiler dependent

Explanation: Order of evaluation of function arguments is undefined.

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Q9. Which of the following sorting algorithms has the lowest worst-case time complexity?

• a) Quick Sort
• b) Merge Sort
• c) Bubble Sort
• d) Insertion Sort

Explanation: Merge Sort is O(n log n) in all cases.

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Q10. In SQL, which command is used to remove all records from a table but keep the table structure?

• a) DELETE
• b) DROP
• c) TRUNCATE
• d) REMOVE

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Programming Concepts (Questions 11-12)

Q11. What is the time complexity of inserting an element at the beginning of an array?

• a) O(1)
• b) O(n)
• c) O(log n)
• d) O(n²)

Explanation: All existing elements need to be shifted.

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Q12. Which of the following is true about interfaces in Java?

• a) They can have constructors
• b) They can have method implementations
• c) They can have static methods
• d) They can be instantiated

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Coding Questions (Questions 13-15)

Q13. Write a program to find the number of occurrences of each character in a string.

Solution:

def char_frequency(s):
    freq = {}
    for char in s:
        if char in freq:
            freq[char] += 1
        else:
            freq[char] = 1
    return freq

s = input()
result = char_frequency(s)
for char, count in sorted(result.items()):
    print(f"{char}: {count}")

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Q14. Write a program to check if two strings are anagrams.

Solution:

#include<stdio.h>
#include<string.h>

int areAnagrams(char *s1, char *s2) {
    int count[256] = {0};
    int i;
    
    if(strlen(s1) != strlen(s2))
        return 0;
    
    for(i = 0; s1[i] && s2[i]; i++) {
        count[s1[i]]++;
        count[s2[i]]--;
    }
    
    for(i = 0; i < 256; i++)
        if(count[i] != 0)
            return 0;
    
    return 1;
}

int main() {
    char s1[100], s2[100];
    scanf("%s %s", s1, s2);
    if(areAnagrams(s1, s2))
        printf("Anagrams");
    else
        printf("Not Anagrams");
    return 0;
}

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Q15. Write a program to implement binary search.

Solution:

import java.util.Scanner;

public class BinarySearch {
    static int binarySearch(int arr[], int key) {
        int left = 0, right = arr.length - 1;
        while(left <= right) {
            int mid = left + (right - left) / 2;
            if(arr[mid] == key)
                return mid;
            if(arr[mid] < key)
                left = mid + 1;
            else
                right = mid - 1;
        }
        return -1;
    }
    
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int arr[] = new int[n];
        for(int i = 0; i < n; i++)
            arr[i] = sc.nextInt();
        int key = sc.nextInt();
        int result = binarySearch(arr, key);
        System.out.println(result);
    }
}

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Topic-Wise Weightage

Section	Weightage	Difficulty
Aptitude	25%	Moderate-Hard
Logical Reasoning	20%	Moderate
Technical MCQs	20%	Moderate-Hard
Coding	35%	Hard

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Preparation Tips for Infosys SP & DSE

1. Quantitative Aptitude

• Focus on advanced topics
• Practice complex word problems
• Study probability and permutations deeply
• Improve calculation speed

2. Logical Reasoning

• Practice complex puzzles
• Focus on data sufficiency
• Solve syllogism problems
• Practice seating arrangements

3. Technical Preparation

• Master data structures
• Study OOPs concepts thoroughly
• Practice SQL queries
• Learn OS and CN basics

4. Coding Skills

• Practice daily on LeetCode/HackerRank
• Focus on arrays, strings, linked lists
• Learn dynamic programming basics
• Write optimized, clean code

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Infosys SP vs DSE - Which to Target?

Factor	SP	DSE
Coding Difficulty	Very High	High
Package	₹8-9 LPA	₹6-7 LPA
Work Type	Core programming	Digital tech
Growth	Technical track	Mixed track

Recommendation: Apply for both to maximize your chances!

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You May Also Like

• Infosys Off Campus 2026
• Infosys Salary Freshers 2026
• Infosys Exam Pattern 2026
• Infosys Interview Questions 2026

Frequently Asked Questions (FAQs)

Q1. Can I apply for both SP and DSE? A: Yes, you can apply for both if you meet the eligibility criteria.

Q2. What is the main difference between SP and DSE? A: SP focuses on core programming skills with higher package, while DSE focuses on digital technologies.

Q3. Is there a separate exam for SP and DSE? A: Usually yes, SP has a more rigorous coding assessment.

Q4. What coding languages can I use? A: C, C++, Java, and Python are commonly supported.

Q5. How important are projects for SP/DSE? A: Projects demonstrate practical skills and can give you an edge in interviews.

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Related Resources:

• Infosys Exam Pattern 2026
• Infosys Placement Papers 2026
• Infosys Off Campus 2026

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All the best for your Infosys SP & DSE preparation! 🎯